matematika tolong di jawab!!!

1. diket :
tinggi tab = 21
r tab = 6

dit :
luas selimut (ls)

jawab :
ls = 2 π r t
= 2 x 22/7 x 6 x 21
= 44 x 6 x 3
= 792

2. diket :
ls = 220
t = 7

dit :
jari2 (r)

jawab :
ls = 2 π r t
220 = 2 x 22/7 x r x 7
220 = 44r
r = 220/44
r = 5

3. diket :
t. tab = 10
d = 14 => r = 7

dit :
a. luas tab
b. luas selimut tab
c. luas tab tanpa tutup
d. luas sisi tabung

jawab :
a. luas tab : 2 x π x r (r + t)
= 2 x 22/7 x 7 (7 + 10)
= 44 x 17
= 748

b. ls tab = 2 x π x r x t
= 2 x 22/7 x 7 x 10
= 44 x 10
= 440

c. luas tab tanpa tutup
= π x r ( r + 2t )
= 22/7 x 7 (7 + 2 x 10)
= 22 ( 7 + 20 )
= 22 x 27
= 594

d. luas sisi tab
= ( 2 x 22/7 x r x r ) + ( 2 x 22/7 x r x t )
= ( 2 x 22/7 x 7 x 7 ) + ( 2 x 22/7 x 7 x 10 )
= ( 44 x 7 ) + ( 44 x 10 )
= 308 + 440
= 748

semoga membantu:)