Tentukan persamaan garis yang melalui A (-4, 5) dan m=1/7

(y-y1)=m (x-x1)
(y-5) = 1/7 (x-(-4))
( y-5 = 1/7x + 4/7 )x7
7y - 35 = x +4
7y-x = 39

بِسْمِ اللَّهِ الرَّحْمَنِ الرَّحِيمِ

m = 1/7 
x1 = -4 
y1 = 5 

Pers Garis  = 

m = Δy/Δx
m = (y-y1)/(x-x1) 
1/7 = (y-5)/(x+4)
x+4 = 7y -35 = 0 
x - 7y + 39 = 0 

SEMOGA MEMBANTU