Matematika

Pertanyaan

(a+b)+(a+3b)+(a+5b)+....+(a+31b)sn=
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1 Jawaban

  • a+b)+(a+3b)+(a+5b)+...+(a+31b),

    .b=2b
    U1 =(a+b)
    Un = (a+31b)

    Un = u1 +(n-1) b
    (a+31b) = (a+b) +(n-1) 2b
    (a+36b) - (a+b) = (n-1) 2b
    31b -b = (n-1) 2b
    (31b-b) /2b = ( n-1)
    30b / 2b = (n-1)
    15 = n-1
    15+1 =n
    16 =n

    Sn = n/2 (u1 +un)
    = 16/2 ( a+b +a+31b)
    = 8 (2a+32b)
    = 16a+256b

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