sistem persamaan (a-2)x+y=0 x+(a-2)y=0 tidak hanya (y,x)=(0.0) saja maka nilai a*2-4a+3=...

(a - 2)x + y = 0
y = -(a - 2)x ... (1)

x + (a - 2)y = 0
x + (a - 2)(-(a - 2))x = 0
x(1 - (a - 2)²) = 0
1 - (a - 2)² = 0
(a - 2)² = 1
a - 2 = 1 atau a - 2 = -1
a = 3 atau a = 1

utk a = 1
a² - 4a + 3 = 1² - 4.1 + 3 = 0

utk a = -1
a² - 4a + 3 = (-1)² - 4(-1) + 3 = 1 + 4 + 3 = 8