Air massa 200 gr pada suhu 20 dapat celcius di beri kalori 16 kekal,maka suhu akhir air tersebut adalah...

Diket :
Massa air, m = 200 gram
Suhu awal, T1 = 20°C
Kalor, Q = 16 kkal = 16000 kal
Kalor jenis air, c air = 1 kal/gram°C

Tanya :
Suhu akhir, T2 = __?

Jawab :
Step 1
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Cari dulu beda suhu, ΔT = __?
Q = m.c air.ΔT
16000 = 200•1•ΔT
16000 = 200•ΔT
ΔT = 16000/200
ΔT = 80°C

Step 2
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ΔT = T2 - T1
80°C = T2 - 20°C
T2 = 80°C + 20°C

T2 = 100°C

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FZA