Integral subtitusi dari (2×+5) pangkat 9 dx ?

u = 2x + 5
du/dx = 2
dx = du/2

Integral (u)^9 dx
Integral (u)^9 du/2
= 1/2 × 1/10 (u)^10 + c
= 1/20 (u)^10 + c
= 1/20 (2x + 5)^10 + c

misal :

t = (2x + 5)

= int (2x + 5)^9 dx
= int t^9 dx
= 1/(9+1) t^(9+1) + c
= (1/10) t^10 + c
= (1/10) (2x + 5)^10 + c

semoga berguna +_+