ada yang bisa bantu tolong

∫ x² - 2x + 5 dx
=>⅓ x³ - x² + 5x + C

f(0)=0 - 0 + 0 +C=5
C=5

Jadi f(x)=⅓ x³ - x² +5x + 5

Bab Integral
Matematika SMA Kelas XI

∫ (x² - 2x - 5) dx = (1/(2 + 1)) x¹⁺² - 2/(1 + 1) . x¹⁺¹ - 5x
                         = (1/3) x³ - (2/2) x² - 5x
                         = (1/3) x³ - x² - 5x + C

f(0) = 0 - 0 - 0 + C = 5
C = 5

f(x) = (1/3) x³ - x² - 5x + 5