Matematika

Pertanyaan

Buktikan rumus-rumus trigonometri ini!

sin A + sin B = 2 sin [(A + B) / 2] cos [(A - B) / 2]
sin A - sin B = 2 cos [(A + B) / 2] sin [(A - B) / 2]
cos A + cos B = 2 cos [(A + B) / 2] cos [(A - B) / 2]
cos A - cos B = -2 sin [(A + B) / 2] sin [(A - B) / 2]

1 Jawaban

Pertanyaan Lainnya