1 mol glukosa, air = 200 gram = 0,2 kg berapa delta Tb ?
Kimia
iinasri
Pertanyaan
1 mol glukosa, air = 200 gram = 0,2 kg
berapa delta Tb ?
berapa delta Tb ?
1 Jawaban
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1. Jawaban ramaji
m glukosa = mol glukosa/massa pelarut
m glukosa = 1/0,2
m glukosa = 5 molal
(Kb air = 0,52 °C/m)
∆Tb = Kb × m
∆Tb = 0,52 × 5
∆Tb = 2,6 °C