1 mol Nacl → n = 2, alfa = 1 air = 200 gram→0,2 kg Berapa delta Tb ? (Rumus : delta Tb=kb.m.I)

m NaCl = mol NaCl/massa pelarut
m NaCl = 1/0,2
m NaCl = 5 molal
i = 1 + (n-1)alfa
i = 1 + (2-1)1
i = 2
(Kb air = 0,52 °C/m)
∆Tb = Kb × m × i
∆Tb = 0,52 × 5 × 2
∆Tb = 5,2 °C