1 per x log x pangkat 2 -4 = 1 per x log (5x-1)

Logaritma

1/x'log (x² - 4) = 1/x'log (5x - 1)
x² - 4 = 5x - 1
x² - 4 - 5x + 1 = 0
x² - 5x - 3 = 0

Akar2 dr x² - 5x - 3 = 0
x1.2 = (-b ± √(b² - 4ac))/(2a)
x1.2 = (-(-5) ± √((-5)² - 4.1(-3))/(2.1)
x1.2 = (5 ± √(25 + 12))/2
x1.2 = (5 ± √37)/2

Ambil akar yg bernilai positif (+),
Krn syarat basis (a > 0 dan a ≠ 1) dan numerus (b > 0) dr logaritma (a'log b).

Nilai x yang memenuhi :
x = (5 + √37)/2