Fungsi f : R->R dan g : R->R ditentukan oleh rumus f(x) = x - 3 dan g (x) = 2x + 3. Tentukanlah (g o f)*pangkat-1* (x)

f(x) = x - 3 dan g(x) = 2x + 3, maka

(gof)(x) = g(f(x)) = g(x-3) = 2(x-3) + 3 = 2x - 6 + 3 = 2x - 3
misal y = (gof)(x), jadi
y = 2x - 3
2x = y + 3
x = (y + 3)/2
(gof)^-1 (y) = (y+3)/2
(gof)^-1 (x) = (x + 3)/2