Diketahui balok PQ,RS,TU,VW, diketahui PQ=8cm QR=4cm PT=6cm tentukan panjang QW

qw^2=pw^2+pq^2
ps=qr; pw^2=pt^2+ps^2=52
qw^2= 52+64=116
qw=akar 116= 12,884 cm?

QW = diagonal ruang
= √(p^2 + l^2 + t^2)
= √(8^2 + 4^2 + 6^2)
= √(64 + 16 + 36)
= √116
= √4√29
= 2√29 cm