diketahuai penyelesaian 3^2x^+x^-2=81^x^+2 adalah p dan q.jika p>,nilai p-q adalah?

Eksponensial

(3)²ˣ⁻ˣ² = (81)ˣ⁺²
(3)²ˣ⁻ˣ² = (3⁴)ˣ⁺²
..
2x - x² = 4(x + 2)
2x - x² = 4x + 8
x² + 4x - 2x + 8 = 0
x² + 2x + 8 = 0 , akar akarnya p  dan q
a =1 , b =  2 , c = 8

p+ q = -b/a = -2/1 = - 2
p. q = c/a = 8/1 = 8
.
p- q = √(p-q)²
p- q = √ {(p²+q)²- 2 pq}
p - q = √{(p+q)² - 4 pq}
p - q = √{ (-2)² - 4(8)}
p - q = √(4 - 32)
p - q = √-28
p - q = 28√i