nomer 4 dan 5 gimana carany? (eksponensial)
Matematika
cantikabella20
Pertanyaan
nomer 4 dan 5 gimana carany?
(eksponensial)
(eksponensial)
1 Jawaban
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1. Jawaban DB45
Ekponensial
4/5 (2)³ˣ⁻² + 8ˣ/20 = 1 ...kalikan 20
4(4)(2)³ˣ⁻² + (8)ˣ = 20
16 (2)³ˣ (2)⁻² + (2)³ˣ = 20
16/4 (2)³ˣ + (2)³ˣ = 20
4(2)³ˣ + (2)³ˣ = 20
5 (2)³ˣ = 20
(2)³ˣ = 20/5 = 4 = (2)²
3x = 2
x = 2/3
5)
p = 3x + y
(27ˣ) = (81)(9^y)
(3)³ˣ = (3⁴)(3)^(2y)
3x = 4 + 2y --> 3x - 2y = 4 .... (1)
5(25ˣ) = 3.125^y
5(5)²ˣ = (5⁵)^y
1 + 2x = 5y --> 2x - 5y = -1 ....(2)
.
(1), (2) eliminasi
3x - 2y = 4...|kali 2
2x - 5y = -1..|kali 3
.
6x - 4y = 8
6x - 15y = - 3
...kurangkan...
11 y = 11
y = 1
.
3x - 2y = 4
3x - 2(1)= 4
3x = 4 +2 = 6
x = 2
p = 3x + y
p = 3(2) +(1)
p = 6 + 1
p = 7Pertanyaan Lainnya