Matematika

Pertanyaan

nomer 4 dan 5 gimana carany?
(eksponensial)
nomer 4 dan 5 gimana carany? (eksponensial)

1 Jawaban

  • Ekponensial

    4/5 (2)³ˣ⁻² + 8ˣ/20 = 1 ...kalikan 20
    4(4)(2)³ˣ⁻² +  (8)ˣ = 20
    16 (2)³ˣ (2)⁻² + (2)³ˣ = 20
    16/4 (2)³ˣ + (2)³ˣ =  20
    4(2)³ˣ + (2)³ˣ = 20
    5 (2)³ˣ = 20
    (2)³ˣ = 20/5 = 4 = (2)²
    3x = 2
    x = 2/3

    5) 
    p =  3x + y

    (27ˣ) = (81)(9^y)
    (3)³ˣ = (3⁴)(3)^(2y)
    3x = 4 + 2y --> 3x - 2y = 4 .... (1)

    5(25ˣ) = 3.125^y
    5(5)²ˣ = (5⁵)^y
    1 + 2x = 5y --> 2x - 5y = -1 ....(2)
    .
    (1), (2) eliminasi

    3x - 2y = 4...|kali 2
    2x - 5y = -1..|kali 3
    .
    6x - 4y = 8
    6x - 15y = - 3
    ...kurangkan...
    11 y = 11
    y = 1
    .
    3x  - 2y = 4
    3x - 2(1)= 4
    3x = 4 +2 = 6
    x = 2

    p = 3x + y
    p = 3(2) +(1)
    p = 6 + 1
    p = 7
    Gambar lampiran jawaban DB45