materi kelas x bentuk akar [tex]sederhanakanlah:[/tex] [tex]a) 12 \sqrt{6} -7 \sqrt{6}+3 \sqrt{6} = b) \sqrt{12} + \sqrt{27} + \sqrt{75} = c) ( \sqrt{20}-3
Matematika
wardhanabagas
Pertanyaan
materi kelas x bentuk akar
[tex]sederhanakanlah:[/tex]
[tex]a) 12 \sqrt{6} -7 \sqrt{6}+3 \sqrt{6} =
b) \sqrt{12} + \sqrt{27} + \sqrt{75} =
c) ( \sqrt{20}-3 \sqrt{3} (2 \sqrt{5} + \sqrt{27} =
tentukan nilai x dari;
a) 128 ^{8x-2} = 2 ^{10+x}
b) \sqrt{3} ^{x+3} =( \frac{1}{3}) ^{6-x}
coba yang bisa
[/tex]
[tex]sederhanakanlah:[/tex]
[tex]a) 12 \sqrt{6} -7 \sqrt{6}+3 \sqrt{6} =
b) \sqrt{12} + \sqrt{27} + \sqrt{75} =
c) ( \sqrt{20}-3 \sqrt{3} (2 \sqrt{5} + \sqrt{27} =
tentukan nilai x dari;
a) 128 ^{8x-2} = 2 ^{10+x}
b) \sqrt{3} ^{x+3} =( \frac{1}{3}) ^{6-x}
coba yang bisa
[/tex]
1 Jawaban
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1. Jawaban Flash131
a) √6 (12 - 7 + 3)
= √6 ( 2 )
= 2 √6
b) √12 + √27 + √75
= √3 √4 + √3 √9 + √3 √25
= 2 √3 + 3√3 + 5√3
= √3 (2 + 3 + 5)
= √3 (8)
= 8 √3
c) (√20 - 3√3( 2√5 + √27 ))
= ( √20 - 6 √15 - 3 √81 )
= ( √4 √5 - 6 √3 √5 - 3 . 9 )
= ( 2 √5 - 6 √3 √5 - 27 )
= 2√5 - 6√15 - 27
a)128⁸ˣ⁻² = 2¹⁰⁺ˣ
2⁷⁽⁸ˣ⁻²⁾ = 2 ¹⁰⁺ˣ
7(8x - 2) = 10 + x
56x - 14 = 10 + x
55x = 25
11x = 5
x = 5/11
√3ˣ⁺³ = (1/3)⁶⁻ˣ
3⁽ˣ⁺³⁾ˣ¹/² = 3⁽⁻¹⁾⁽⁶⁻ˣ⁾
(x + 3)/2 = -6 + x
x + 3 = -12 + 2x
x = 15