Matematika

Pertanyaan

materi kelas x bentuk akar

[tex]sederhanakanlah:[/tex]

[tex]a) 12 \sqrt{6} -7 \sqrt{6}+3 \sqrt{6} =

b) \sqrt{12} + \sqrt{27} + \sqrt{75} =

c) ( \sqrt{20}-3 \sqrt{3} (2 \sqrt{5} + \sqrt{27} =

tentukan nilai x dari;

a) 128 ^{8x-2} = 2 ^{10+x}

b) \sqrt{3} ^{x+3} =( \frac{1}{3}) ^{6-x}



coba yang bisa
[/tex]

1 Jawaban

  • a) √6 (12 - 7 + 3)
     = √6 ( 2 )
     = 2 √6

    b) √12 + √27 + √75
    = √3 √4 + √3 √9 + √3 √25
    = 2 √3 + 3√3 + 5√3
    = √3 (2 + 3 + 5)
    = √3 (8)
    = 8 √3

    c) (√20 - 3√3( 2√5 + √27  ))
    = ( √20 - 6 √15 - 3 √81 )
    = ( √4 √5 - 6 √3 √5 - 3 . 9 )
    = ( 2 √5 - 6 √3 √5 - 27 )
    = 2√5 - 6√15 - 27



    a)128⁸ˣ⁻² = 2¹⁰⁺ˣ
    2⁷⁽⁸ˣ⁻²⁾ = 2 ¹⁰⁺ˣ
    7(8x - 2) = 10 + x
    56x - 14 = 10 + x
    55x = 25
    11x = 5
    x = 5/11

    √3ˣ⁺³ = (1/3)⁶⁻ˣ
    3⁽ˣ⁺³⁾ˣ¹/² = 3⁽⁻¹⁾⁽⁶⁻ˣ⁾
    (x + 3)/2 = -6 + x
    x + 3 = -12 + 2x
    x = 15

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