Quiz Math - Number Theory Notice. No-step answers/spam will be deleted.

[tex]a^{2}+b^{2}=0[/tex]
[tex](a+bi)(a-bi)=0[/tex]

kasus 1:
[tex]a=-bi[/tex]
[tex]\frac{a+b}{a-b}=\frac{-bi+b}{-bi-b}=0[/tex]
[tex]=\frac{b(-i+1)}{b(-i-1)}=0[/tex]
[tex]=\frac{-i+1}{-i-1}*\frac{-i+1}{-i+1}[/tex]
[tex]=\frac{(-i+1)^{2}}{i^{2}-1}[/tex]
[tex]=\frac{-i^{2}-2i+1}{-1-1}[/tex]
[tex]=\frac{-1-2i+1}{-2}[/tex]
[tex]=i=\sqrt{-1}[/tex]

kasus 2:
[tex]a=+bi[/tex]
[tex]\frac{a+b}{a-b}=\frac{bi+b}{bi-b}=0[/tex]
[tex]=\frac{b(-i+1)}{b(-i-1)}=0[/tex]
[tex]=\frac{i+1}{i-1}*\frac{i+1}{i+1}[/tex]
[tex]=\frac{(i+1)^{2}}{i^{2}-1}[/tex]
[tex]=\frac{i^{2}+2i+1}{-1-1}[/tex]
[tex]=\frac{-1+2i+1}{-2}[/tex]
[tex]=-i=-\sqrt{-1}[/tex]

jawabannya E