yg tau tolong bantuin pke cara substitusi
Matematika
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Pertanyaan
yg tau tolong bantuin pke cara substitusi
1 Jawaban
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1. Jawaban v1r4
1.) 3p = -q -10⇒ 3p + q = -10 (x3) ⇒ 9p + 3q = -30
2p +3q = -16 (x1) ⇒ 2p + 3q = -16
____________ _
7p + 0 = -14
p = -14/7
p = -2
2.) 5x + 2y = 6 (x3) ⇒ 15x + 6y = 18
4x + 3y = 2 (x2) ⇒ 8x + 6y = 4
____________ _
7x + 0 = 14
x = 14/7 = 2
5x + 2y = 6
5(2) +2y = 6
10 + 2y = 6
2y = 6 - 10
2y = -4
y = -4/2 = -2
nilai x . y = 2 x (-2) = -4
3.) 3p + 7q = 1 (x-3)⇒ -9p -21q = -3
2p - 3q = 16 (x7) ⇒ 14p - 21q = 115
____________ _
-23p + 0 = -115
p = -115/-23 = 5
3p + 7q = 1
3(5) + 7q = 1
15 + 7q = 1
7q = 1 - 15
7q = -14
q = -14/7 = -2
nilai pxq = 5 x (-2) = -10
4.) 3x1 + 4y1 = 7 (x3) ⇒ 9x1 + 12y1 = 21
-2x1 + 3y1 = -16(x4) ⇒ -8x1 + 12y1 = -64
_______________ _
17x1 + 0 = 85
x1 = 85/17 = 5
3x1 + 4y1 = 7
3(5) + 4y1 = 7
15 + 4y1 = 7
4y1 = 7 - 15
4y1 = -8
y1 = -8/4 = -2
jadi nilai 2x1 - 7y1
2(5) - 7(-2)
= 10 + 14
= 24