(30^2)^4 . 49^6 / 28^5 . 96^2 . 625^2 = 2^a . 3^b . 5^c . 7^d. tentukan a, b, c, dan d !

(30^2)^4 . 49^6 / 28^5 . 96^2 . 625^2 = 2^a . 3^b . 5^c . 7^d

(2×3×5)^8 . (7^2)^6 / (2^2×7)^5 . (2^5×3)^2 . (5^4)^2 = 2^a . 3^b . 5^c . 7^d

2^8 × 3^8 × 5^8 × 7^12 / 2^10 ×7^5 ×2^10×3^2×5^8 = 2^a × 3^b × 5^c × 7^d

2^8-10-10 × 3^8-2 × 5^8-8 × 7^12-5 = 2^a × 3^b × 5^c × 7^d

2^-12 × 3^6 × 5^0 × 7^7 = 2^a × 3^b × 5^c × 7^d

jadi a= - 12 , b= 6, c= 0, d=7...

jadikan yg terbaik jika suka