(2√27-√15) (6√3+√15)
Matematika
Kyukyu30
Pertanyaan
(2√27-√15) (6√3+√15)
2 Jawaban
-
1. Jawaban missdiyun
(2akar27 - akar 15) (6akar 3 + akar 15)
=2akar 27 (6 akar 3 + akar 15) - akar 15 (6 akar 3 + akar 15)
= 12 akar (27×3) + 2 akar (27×15) - 6 akar (15×3) - akar (15×15)
= 12 akar 81 + 2 akar 405 - 6akar 45 - akar (15^2)
= (12 × 9) + 2 akar (81×5) - 6 akar (9×5) - 15
= (108 - 15) + (2akar 81 × akar 5) - (6 akar 9 × akar 5)
= 93 + (2 × 9 ×akar5) - (6 × 3 × akar 5)
= 93 + 18 akar 5 - 18 akar 5
= 93 + 0
= 93
semoga membantu -
2. Jawaban BSunShine
Huruf V = melambangkan akar
●◇◇◇◇◇◆◆◆◆◆◇◇◇◇◇◆◆◆◆◆●
(2V27 - V15) (6V3 + V15)
》12V81 + 2V405 - 6V45 - 15
》 12.9 + 2V81.5 - 6V9.5 - 15
》 108 + 2.9V5 - 6.3V5 -15
》 108 - 15 + 18V5 - 18V5
》 93